3 Responses to “A straight line over ocean without hitting land between Pakistan and Russia”

  1. 67) The distance across the Irish Sea from the Isle of Man’s Douglas Harbor to Great Orm’s Head in North Wales is 60 miles. If the Earth was a globe then the surface of the water between them would form a 60 mile arc, the center towering 1944 feet higher than the coastlines at either end. It is well-known and easily verifiable, however, that on a clear day, from a modest altitude of 100 feet, the Great Orm’s Head is visible from Douglas Harbor. This would be completely impossible on a globe of 25,000 miles. Assuming the 100 foot altitude causes the horizon to appear approximately 13 miles off, the 47 miles remaining means the Welsh coastline should still fall an impossible 1472 feet below the line of sight!

    69) The New York City skyline is clearly visible from Harriman State Park’s Bear Mountain 60 miles away. If Earth were a ball 25,000 miles in circumference, viewing from Bear Mountain’s 1,283 foot summit, the Pythagorean Theorem determining distance to the horizon being 1.23 times the square root of the height in feet, the NYC skyline should be invisible behind 170 feet of curved Earth.

    70) From Washington’s Rock in New Jersey, at just a 400 foot elevation, it is possible on a clear day to see the skylines of both New York and Philadelphia in opposite directions at the same time covering a total distance of 120 miles! If Earth were a ball 25,000 miles in circumference, both of these skylines should be hidden behind over 800 feet of Earth’s curvature.


    • ian says:

      It’s 66 feet in 100 miles Adam.

      • ian says:

        Best Answer: Measuring a mile along the equator:

        1 mile = 1.609344 km

        Radius (r) of earth along the equator = 6,378.137 km [source 1]

        The angle in radians (a) between two points a distance (s) along the circumference of circle of radius (r) is:

        a = s/r

        We have measured one mile around, so
        r = 6378137 metres
        s = 1609.344 metres

        a = 0.000252321356479612434

        The distance along the radius that we have moved by moving around the earth is:

        r – (r * cos(a))

        cos(a) = 0.99999996816681556656998075613651
        r * cos(a) = 6378136.7969635885373159573500023 metres

        r – r cos(a) = 0.2030364 metres

        So, for every mile around the circumference of the earth, the curvature drops by 20.3 cm, which is 7.994 inches.
        Source(s): [1] http://en.wikipedia.org/wiki/Earth_radius

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